anonymous
  • anonymous
a particle moves along the x-axis so that at time t >(or equal to) 0 its position is given by x(t)=2t^3 - 21t^2 + 72t-53. At what time t is the particle at rest?
Mathematics
chestercat
  • chestercat
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bahrom7893
  • bahrom7893
Particle is at rest when Velocity = 0
bahrom7893
  • bahrom7893
V = X ' ( t ) = 6t^2 - 42t + 72 = 0
bahrom7893
  • bahrom7893
V = t^2 - 7t + 12 = 0

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bahrom7893
  • bahrom7893
Solve for t: t1 = 3 t2 = 4 Particle is at rest at t = 3 and t = 4. Fan me if I helped, thanks!

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