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## anonymous 5 years ago Help please, If the point P in the unit circle that corresponds to a real number t is [5/7, -sqrt6:radicand2/7] find csc(t)?

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1. anonymous

The expression is a bit confusing. Can you rewrite that?

2. anonymous

Did you mean $(\frac{5}{7}, \frac{-2\sqrt6}{7})$

3. anonymous

yes

4. anonymous

I am having so much trouble learning trig at the age of 45 lol

5. anonymous

Any point on the unit circle can be represented by $(\sin(t), \cos(t))$. The angle t isn't important here. What this tells us is that the current angle has a sine of (5/7). And we know that csc(t) = 1/sin(t), so all we do is flip the sine value to get csc(t) for the t in question = 7/5

6. anonymous

oh my.........thank you so much

7. anonymous

so I need to study the trig functions of sin cos, and tan, and then flip for cot, csc, and sec

8. anonymous

You have the right name, lifesaver!

9. anonymous

Make sure you know which one is the inverse of which: csc(t) = 1/sin(t) sec(t) = 1/cos(t) cot(t) = 1/tan(t) just in case

10. anonymous

So......if I have this P on this unit circle that corresponds to a real number (t) and the [-sqrt:7/4, -3/4] and I need to find cot(t) the answer would be the square root of 7/3 right?

11. anonymous

Depends on where you mean to have parenthesis, but even then, still not quite: (sqrt(7))/3 = tan(t). So cot(t) is the inverse of that: 3/(sqrt(7))

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