Write an equation of the line containing the given point and perpendicular to the given line (6, -5); 4x+9y=7
I have tried this problem 2 times it took forever and I got it wrong both times.
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If anyone can help me on that one, i also need to know (-2,3); 7x=5y+3
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For the first question, two lines are perpendicular when their slopes are negative reciprocals (that is to say slope1 times slope2 = -1).
So if you solve the given (4x+9y=7) line in terms of y, you get:
y = (4/9)x-(7/9).
This means the slope of that line is 4/9. So, the slope of the line you are trying to find would be -9/4.
Now use this slope and the given point [(x0,y0)=(6,-5)]
in the equation y-y0=m(x-x0) where m is your slope.
Okay that is what I did but i did not use a negative i kept -9/4 positive
Same process for the other two questions. Solve for y in the given equation, the coefficient of your x is your slope, sub that and your given point into the equation y-y0=m(x-x0) and solve for y again.
I am just horrible at math, I swear what you are saying sounds so confusing to me
Sorry, my mistake. The slope of the given line would be -4/9 so the slope you want to use is 9/4 as you said.
o okay wow. i am so lost, I have this assignment due tonight, and I need like 6 more questions to do, ive worked on them all morning and most of the night and had a family memeber help, I still have no idea what im doing