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anonymous

  • 5 years ago

Write an equation of the line containing the given point and perpendicular to the given line (6, -5); 4x+9y=7 I have tried this problem 2 times it took forever and I got it wrong both times.

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  1. anonymous
    • 5 years ago
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    If anyone can help me on that one, i also need to know (-2,3); 7x=5y+3

  2. anonymous
    • 5 years ago
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    I lied I have another one too: (3,7); x+4y=9

  3. anonymous
    • 5 years ago
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    I need to know these in the next hour.

  4. anonymous
    • 5 years ago
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    For the first question, two lines are perpendicular when their slopes are negative reciprocals (that is to say slope1 times slope2 = -1). So if you solve the given (4x+9y=7) line in terms of y, you get: y = (4/9)x-(7/9). This means the slope of that line is 4/9. So, the slope of the line you are trying to find would be -9/4. Now use this slope and the given point [(x0,y0)=(6,-5)] in the equation y-y0=m(x-x0) where m is your slope.

  5. anonymous
    • 5 years ago
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    Okay that is what I did but i did not use a negative i kept -9/4 positive

  6. anonymous
    • 5 years ago
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    Same process for the other two questions. Solve for y in the given equation, the coefficient of your x is your slope, sub that and your given point into the equation y-y0=m(x-x0) and solve for y again.

  7. anonymous
    • 5 years ago
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    I am just horrible at math, I swear what you are saying sounds so confusing to me

  8. anonymous
    • 5 years ago
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    Sorry, my mistake. The slope of the given line would be -4/9 so the slope you want to use is 9/4 as you said.

  9. anonymous
    • 5 years ago
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    o okay wow. i am so lost, I have this assignment due tonight, and I need like 6 more questions to do, ive worked on them all morning and most of the night and had a family memeber help, I still have no idea what im doing

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