anonymous
  • anonymous
\[\ln 6/\sqrt{x2} + 1\]
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Can you re-write the question using some parentheses for clarity?
anonymous
  • anonymous
\[\ln 6/\sqrt{x2}+1\]
anonymous
  • anonymous
the x means x square

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anonymous
  • anonymous
I wanted to know if the 6...+1 were all in parentheses like this ln(6...+1) Is the '+1' apart of the ln() ?... Because it'll make a difference
anonymous
  • anonymous
the 6 is not within the parentheses. the 6 is by itself. yes the +1 is apart of the in() thanks
anonymous
  • anonymous
[ln 6/sqrt{x2}+1]
anonymous
  • anonymous
wouldn't the square-root of x^2 just be 'x'? The way you wrote the question is ambiguous.
anonymous
  • anonymous
sorry

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