## anonymous 5 years ago The terminal speed (in m/s) of the skydriver can be approximated by square root 40 m, where m is the mass (in kg) of the skydiver. calculate the terminal speed of a 100-kg shydiver. write an exact answer in radical form. simplify the radical by factoring.

1. bahrom7893

Okay let's try to solve this in simple steps.

2. bahrom7893

Terminal velocity equation: $V_t = \sqrt((2mg)/(\rho*A*C_d))$

3. bahrom7893

(everything is under square root)

4. bahrom7893

where: $V_t$ is terminal velocity m is mass of the falling object g is acceleration due to gravity (9.81m/s^2) Cd = drag coefficient ρ = density of the fluid through which the object is falling A = projected area of the object.

5. bahrom7893

In your case, the terminal Velocity is $\sqrt{40*m}$ where m is the mass (in kg) of a skydiver.

6. bahrom7893

So if you need the terminal velocity of a skydiver whose mass is 100kg, then plug in 100kg into the equation above... You didn't even need the terminal velocity equation and all that crap.. sorry I didn't read the question carefully first time

7. bahrom7893

In your case, the terminal Velocity is $\sqrt{40*m}$ where m is the mass (in kg) of a skydiver. If the skydiver's mass is 100kg, then the terminal velocity is: sqrt( 40 * 100 ) = sqrt(400 * 10) = 20sqrt(10)

8. bahrom7893

The answer is 20 * sqrt(10) m/s

9. anonymous

wow that helped alot thanks