anonymous
  • anonymous
for the following set of data find an appropriate regression equation (linear, exponential, or logarithmic) state your reason x: 1,2,3,4,5 y: 112,114, 119, 122, 129
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\sum_{n=1}^{3}i^(n-1)\]
anonymous
  • anonymous
in the second equation the right side of the sigma should read i^(n-1)
bahrom7893
  • bahrom7893
do you mean i as in imaginary number?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

bahrom7893
  • bahrom7893
\[\sum_{n=1}^{3}i^{(n-1)}\] where i^2 =-1?
anonymous
  • anonymous
yes
bahrom7893
  • bahrom7893
\[\sum_{n=1}^{3}i^{n-1} = i^{1-1} + i^{2-1} + i^{3-1}\]
bahrom7893
  • bahrom7893
\[i^0 + i + i^2 = 1 + i -1 = i\]
anonymous
  • anonymous
okay thats what i got, thank you. can you take a look at the problem above that
bahrom7893
  • bahrom7893
oh for that u need to use a calculator, do u want me to write the equation of the line?
anonymous
  • anonymous
yeah i understand that but how would you know which type of regression to use?
bahrom7893
  • bahrom7893
I think you just try every single one, and the one that goes through the most points will be the one to use, because calculator would approximate all equations. So just try all three, and whichever one comes closest to as many points as possible will be the one to use.
bahrom7893
  • bahrom7893
well, that's how I used to do it, back in hs
anonymous
  • anonymous
how do i graph it? i put in the type of regression and then (L1,L2) then how do I graph it?
bahrom7893
  • bahrom7893
okay what calculator are you using?
bahrom7893
  • bahrom7893
Ti 84? 89? 83?
anonymous
  • anonymous
TI-83
bahrom7893
  • bahrom7893
http://www.mathstore.net/graphing-calculators/TI-84/how-to-linear-regression.php
anonymous
  • anonymous
yeah i got that but my graph axis are bolded i dont know how to get out of that i clicked zoom out a couple of times but it wont work
bahrom7893
  • bahrom7893
try zoom fit
anonymous
  • anonymous
its not doing antyhing
bahrom7893
  • bahrom7893
try decimal
anonymous
  • anonymous
what does that mean?
anonymous
  • anonymous
i got it thank you
bahrom7893
  • bahrom7893
okay i gtg now and that meant zoom decimal
anonymous
  • anonymous
nothings graphing though
bahrom7893
  • bahrom7893
which means u have to try a different regression
bahrom7893
  • bahrom7893
and make sure the plots are selected in the y-editor
bahrom7893
  • bahrom7893
sorry i gtg now, will try to respond later again
anonymous
  • anonymous
yeah they are
anonymous
  • anonymous
ok thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.