for the following set of data find an appropriate regression equation (linear, exponential, or logarithmic) state your reason x: 1,2,3,4,5 y: 112,114, 119, 122, 129

- anonymous

- katieb

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- anonymous

\[\sum_{n=1}^{3}i^(n-1)\]

- anonymous

in the second equation the right side of the sigma should read i^(n-1)

- bahrom7893

do you mean i as in imaginary number?

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## More answers

- bahrom7893

\[\sum_{n=1}^{3}i^{(n-1)}\]
where i^2 =-1?

- anonymous

yes

- bahrom7893

\[\sum_{n=1}^{3}i^{n-1} = i^{1-1} + i^{2-1} + i^{3-1}\]

- bahrom7893

\[i^0 + i + i^2 = 1 + i -1 = i\]

- anonymous

okay thats what i got, thank you. can you take a look at the problem above that

- bahrom7893

oh for that u need to use a calculator, do u want me to write the equation of the line?

- anonymous

yeah i understand that but how would you know which type of regression to use?

- bahrom7893

I think you just try every single one, and the one that goes through the most points will be the one to use, because calculator would approximate all equations. So just try all three, and whichever one comes closest to as many points as possible will be the one to use.

- bahrom7893

well, that's how I used to do it, back in hs

- anonymous

how do i graph it? i put in the type of regression and then (L1,L2) then how do I graph it?

- bahrom7893

okay what calculator are you using?

- bahrom7893

Ti 84? 89? 83?

- anonymous

TI-83

- bahrom7893

http://www.mathstore.net/graphing-calculators/TI-84/how-to-linear-regression.php

- anonymous

yeah i got that but my graph axis are bolded i dont know how to get out of that i clicked zoom out a couple of times but it wont work

- bahrom7893

try zoom fit

- anonymous

its not doing antyhing

- bahrom7893

try decimal

- anonymous

what does that mean?

- anonymous

i got it thank you

- bahrom7893

okay i gtg now and that meant zoom decimal

- anonymous

nothings graphing though

- bahrom7893

which means u have to try a different regression

- bahrom7893

and make sure the plots are selected in the y-editor

- bahrom7893

sorry i gtg now, will try to respond later again

- anonymous

yeah they are

- anonymous

ok thanks

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