a train A travel at constant speed of x, behind train A about 80 miles, there is a train B travel at constant speed of thats higher than train A. after 25 minutes train B crash from behind train A.. what is the train B speed before they crash?

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a train A travel at constant speed of x, behind train A about 80 miles, there is a train B travel at constant speed of thats higher than train A. after 25 minutes train B crash from behind train A.. what is the train B speed before they crash?

Mathematics
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You wrote that train A travels 80 miles behind train A? Is that a typo?
train A travel at constant speed of x, behind train A about 80 miles there is a train B, train B travel at constant speed thats higher than train A. after 25 minutes train B crash train A from behind.. what is the train B speed before they crash?
help!!!!!

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sorry i had post it later and fix data that i forgot to give
Do we know initially how fast A or B are going? Because I get an expression of A's speed in terms of B's. (A's speed is 192 mi/hr less than B's). lol.
wait
train A travel at constant speed of x, behind train A about 80 miles there is a train B, train B travel at constant speed thats higher than train A. after 25 minutes train B crash train A from behind, the crash is after train A travel 25miles.. what is the train B speed before they crash?
Oh. Ok, let me rework the problem
Haha ok, this problem is pretty whack. Kind of messed up if it happens in real life.
Can you help me?
Train B must have travelled (80 + 25) miles to catch up to A. If it did that in 25 minutes, then it did that in (25/60) of an hour. If a train travels X miles in Y hours and if it travels at constant speed, then it’s speed is X/Y miles per hour. So divide 105 by (25/60) to get B’s speed.
you mean the train B speed was 252mph and speed train A was 60mph... the answer is absolutely correct.... thank you verifry- student91 =) now i can sleep well =)
Haha. You're welcome

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