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anonymous

  • 5 years ago

I have another question just like my other one but i dont know how to do this one, Find the solution to each system by the addition (elimination) method....4s-5t=18;6s+10t=-8

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  1. anonymous
    • 5 years ago
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    s = 2, t = -2

  2. anonymous
    • 5 years ago
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    ok so how did you do that please explain?

  3. anonymous
    • 5 years ago
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    multiply ur first eqn by 2 and then add it to the second one..ull eliminate the s variable

  4. anonymous
    • 5 years ago
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    ok

  5. anonymous
    • 5 years ago
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    so like this 2(4s)-2(5t)=2(18), 8s-10t=36, 6s+10t=-8 8s-10t=36 14s=28 s=14/28=.5

  6. anonymous
    • 5 years ago
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    s=28/14 =2

  7. anonymous
    • 5 years ago
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    right

  8. anonymous
    • 5 years ago
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    yes

  9. anonymous
    • 5 years ago
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    thats the approach...make the coefficient of one variable the same by multiplying it with a constant..and then eliminate it by adding or subtracting

  10. anonymous
    • 5 years ago
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    ok

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