anonymous
  • anonymous
how do I combine this function? if f(x)=x^2+5x-6 and g(x)=x-1, find (f.g)(x) and (f/g)(x)
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
For the second part, (f/g)(x), just use long or synthetic division. It is saying to divide f(x) by g(x). You should get (x + 6) as you answer. The first part of the problem is unclear. Is it saying f(g(x)),which means f of g of x, or is it saying f(x) times g(x)?
anonymous
  • anonymous
thanks for your reply! im not sure but thats just what it looked like. the dot was in the middle though (f (with dot in middle) g)(x)
anonymous
  • anonymous
Well if it was (fog) which means the same thing as f(g(x)), Then just sub the function g(x) wherever you see an 'x' in the f(x) function. You should get: x^2 +3x -10 Or in factored form... (x+5)(x-2) 2. If it was (f*g)(x), meaning f times g, Then multiply the two functions and obtain a polynomial to the 3rd degree: (x^2 +5x - 6)(x-1) = x^3 + 6x^2 - 11x +6 Or in factored form... (x-1)(x-1)(x+6)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thank you for your help!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.