anonymous
  • anonymous
I need help on my fraction homework.
Mathematics
jamiebookeater
  • jamiebookeater
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sandra
  • sandra
hey nya was helping you in your other one heh
sandra
  • sandra
your other question
anonymous
  • anonymous
I don't understand what you were talking about :(

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sandra
  • sandra
well, let's do another practice problem
anonymous
  • anonymous
No. I need help on my actual problem!!!
sandra
  • sandra
well, you wanted to compare 5 1/3 and 6.7
sandra
  • sandra
to do this, you want to convert 6.7 into a fraction too
anonymous
  • anonymous
YES!
sandra
  • sandra
so the first rule of numbers is, if you multiple *any* number by 1, it is the same number
sandra
  • sandra
so to convert 6.7 into a fraction, you want to multiply it by some version of a fraction by multiplying by some version of 1 - in this case, you can multiple it by 10/10 (which is one)
sandra
  • sandra
so 6.7 * 10/10 = (6.7 * 10)/10 = 67/10
sandra
  • sandra
now we want to convert 5 1/3 to a non-mixed fraction
sandra
  • sandra
to do that, why don't we convert it into "1/3's"
sandra
  • sandra
thirds
sandra
  • sandra
so 5 1/3 = 5 + 1/3 5 = 5 * 3/3 = 15/3 so 5 1/3 = 15/3 + 1/3 = 16/3
sandra
  • sandra
so really, you're comparing 16/3 to 67/10
sandra
  • sandra
it's kind of hard to tell from just that right?
sandra
  • sandra
and so what you have to do, is make sure the bottom number in both of those fractions is the same - that way you can just compare the top numbers to tell which is bigger
sandra
  • sandra
that process is called finding a "common denominator"
sandra
  • sandra
a common bottom number for both fractions
sandra
  • sandra
now this is where our first rule comes back into play - you can multiply any number by "1" and you have the same number
sandra
  • sandra
So we want to make it so 16/3 to 67/10 both have the same bottom number. One way to make sure of that is find some number both of those bottom numbers - 3 and 10 - divide into evenly
anonymous
  • anonymous
Ok, I think I am going 2 find somebody else!
sandra
  • sandra
ok good luck =)

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