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anonymous

  • 5 years ago

how would I solve (2r+3)(2r-1)=-(3r+1)

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  1. anonymous
    • 5 years ago
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    1. Set one side equal to zero. 2. Expand the polynomial. 3. Try to factorize or just complete the square to find the solutions.

  2. anonymous
    • 5 years ago
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    I am not sure how to move the -(3r+1) to the other side, do I foil the left side first, then move the other, or move first and then factor or solve?

  3. anonymous
    • 5 years ago
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    It wouldn't matter. (2r+3)(2r-1)+(3r+1) = 0 & 4r^2 + 4r - 3 = -(3r +1) means the same thing.

  4. anonymous
    • 5 years ago
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    thanks

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