## anonymous 5 years ago Hi again, could anyone help with x3-3x2-4x-12=0 the 3 and 2 after the x's rep. cube and square. Thanks

1. bahrom7893

take a look at this: http://home.scarlet.be/~ping1339/cubic.htm I will try to get to this question later...

2. anonymous

This one's actually easier then it might look at first glance. The key is to realize you can group the first two terms and the last two terms in such a way that you'll get a common polynomial factor. \begin{align} x^3-3x^2-4x-12&=0\\ (x^3-3x^2) - (4x-12) &=0\\ x^2(x-3) - 4(x-3) &=0\\ (x^2-4)(x-3)&=0\\ (x+2)(x-2)(x-3)&=0 \end{align}

3. anonymous

thank you, ALOT