• anonymous
Hi again, could anyone help with x3-3x2-4x-12=0 the 3 and 2 after the x's rep. cube and square. Thanks
  • Stacey Warren - Expert
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  • katieb
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  • bahrom7893
take a look at this: I will try to get to this question later...
  • anonymous
This one's actually easier then it might look at first glance. The key is to realize you can group the first two terms and the last two terms in such a way that you'll get a common polynomial factor. \[ \begin{align} x^3-3x^2-4x-12&=0\\ (x^3-3x^2) - (4x-12) &=0\\ x^2(x-3) - 4(x-3) &=0\\ (x^2-4)(x-3)&=0\\ (x+2)(x-2)(x-3)&=0 \end{align} \]
  • anonymous
thank you, ALOT

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