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anonymous
 5 years ago
Hi again, could anyone help with
x33x24x12=0
the 3 and 2 after the x's rep. cube and square. Thanks
anonymous
 5 years ago
Hi again, could anyone help with x33x24x12=0 the 3 and 2 after the x's rep. cube and square. Thanks

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0take a look at this: http://home.scarlet.be/~ping1339/cubic.htm I will try to get to this question later...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This one's actually easier then it might look at first glance. The key is to realize you can group the first two terms and the last two terms in such a way that you'll get a common polynomial factor. \[ \begin{align} x^33x^24x12&=0\\ (x^33x^2)  (4x12) &=0\\ x^2(x3)  4(x3) &=0\\ (x^24)(x3)&=0\\ (x+2)(x2)(x3)&=0 \end{align} \]
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