anonymous
  • anonymous
4a/5 divided by a^2 -16/3 I am so lost, and help would be great!
Mathematics
schrodinger
  • schrodinger
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bahrom7893
  • bahrom7893
okay so did you mean: \[(4a/5) / (a^2 - (16/3))\]?
anonymous
  • anonymous
yes, I wasnt exactly sure how to put it on here
bahrom7893
  • bahrom7893
okay first, look at the denominator: \[a^2 - 16/3\]

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bahrom7893
  • bahrom7893
Simplify it (find the common denominator): \[a^2 - (16/3) = (3a^2-16)/3\]
bahrom7893
  • bahrom7893
Now rewrite this: \[(4a/5) / (a^2 - (16/3)\] As: \[(4a/5)/((3a^2-16)/3)\]
bahrom7893
  • bahrom7893
Dividing by a fraction is the same as multiplying by its inverse.
bahrom7893
  • bahrom7893
\[(4a/5) * (3/(3a^2-16))\]
bahrom7893
  • bahrom7893
Simplify:
bahrom7893
  • bahrom7893
\[12a/(5(3a^2 - 16))\]
bahrom7893
  • bahrom7893
so what is the question? simplify it, or is it equal to something and u have to solve for a. I mean you can't really simplify this
bahrom7893
  • bahrom7893
this is as neat as it gets
anonymous
  • anonymous
it is simplify... this class is beating the ---- outta me!
bahrom7893
  • bahrom7893
well that's as much as you can simplify it if the original expression is correct. Click on Become a fan if I helped, lol I'm trying to see what comes after superhero. Thanks!
anonymous
  • anonymous
thank you so much for your help, I really appreciate it! I have clicked on Become a Fan! You are awesome!
bahrom7893
  • bahrom7893
lol thanx!

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