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anonymous

  • 5 years ago

4a/5 divided by a^2 -16/3 I am so lost, and help would be great!

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  1. bahrom7893
    • 5 years ago
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    okay so did you mean: \[(4a/5) / (a^2 - (16/3))\]?

  2. anonymous
    • 5 years ago
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    yes, I wasnt exactly sure how to put it on here

  3. bahrom7893
    • 5 years ago
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    okay first, look at the denominator: \[a^2 - 16/3\]

  4. bahrom7893
    • 5 years ago
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    Simplify it (find the common denominator): \[a^2 - (16/3) = (3a^2-16)/3\]

  5. bahrom7893
    • 5 years ago
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    Now rewrite this: \[(4a/5) / (a^2 - (16/3)\] As: \[(4a/5)/((3a^2-16)/3)\]

  6. bahrom7893
    • 5 years ago
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    Dividing by a fraction is the same as multiplying by its inverse.

  7. bahrom7893
    • 5 years ago
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    \[(4a/5) * (3/(3a^2-16))\]

  8. bahrom7893
    • 5 years ago
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    Simplify:

  9. bahrom7893
    • 5 years ago
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    \[12a/(5(3a^2 - 16))\]

  10. bahrom7893
    • 5 years ago
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    so what is the question? simplify it, or is it equal to something and u have to solve for a. I mean you can't really simplify this

  11. bahrom7893
    • 5 years ago
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    this is as neat as it gets

  12. anonymous
    • 5 years ago
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    it is simplify... this class is beating the ---- outta me!

  13. bahrom7893
    • 5 years ago
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    well that's as much as you can simplify it if the original expression is correct. Click on Become a fan if I helped, lol I'm trying to see what comes after superhero. Thanks!

  14. anonymous
    • 5 years ago
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    thank you so much for your help, I really appreciate it! I have clicked on Become a Fan! You are awesome!

  15. bahrom7893
    • 5 years ago
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    lol thanx!

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