anonymous
  • anonymous
Not sure on this one at all... :( mx+3x+my+3y/m^2-3m-18
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
are those quantities like (mx+3x+my+3y) / (m^2-3m-18)
anonymous
  • anonymous
yeah sorry...
anonymous
  • anonymous
ok so what are you solving for?

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anonymous
  • anonymous
It just says simplify...
anonymous
  • anonymous
oh ok... if you look at the denominator you see that m^2 - 3m - 18 factors pretty nicely into (m-6)(m+3) and if you look at the numerator...its a little tricky to see if you aren't used to factoring but you can group them and then factor so you have mx+3x+my+3y so collect some terms that are similar in the first two and the last two x(m+3) + y(m+3) and then since both contain the common factor (m+3) you can group the x and y so you get (x+y)(m+3) / (m-6)(m+3) the (m+3) cancels you end up with (x+y)/(m-6) if you are stuck on the factoring, trying FOIL-ing (x+y)(m+3) you will get the exact same thing that we started out with
anonymous
  • anonymous
Thank you so much!
anonymous
  • anonymous
no problem

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