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anonymous
 5 years ago
When a particle is located a distance x meters from the origin, a force of 2cos(pix/6) newtons acts on it. How much work W is done in moving the particle from x = 1 to x = 5?
anonymous
 5 years ago
When a particle is located a distance x meters from the origin, a force of 2cos(pix/6) newtons acts on it. How much work W is done in moving the particle from x = 1 to x = 5?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is this calculus based physics?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will assume that this is a calculus based physics question. W = F * D Here the force is variable, so: integral 2cos(pix/6) dx from lower limit 1 to upper limit 5.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, i got stumped because of the negative force. what does that mean? doesnt force have to be positive

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the positive and negative direction here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A force can always work against a system in which you ascribe a vector to be positive.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what is positive and what is negative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you make an example

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The most simple example would probably be gravity.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't let semantics play with your mind, you can designate whichever direction you choose as postive or negative.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so a particle along the x axis , or x meters from the origin experiences a force 2cos (pix/6). what direction is positive and what is negative. it can be up or down?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but positive and negative are like east /west or north south, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0graph the function that you have, look at interval x=1 to x=5 and you'll understand how you can have a negative force here.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are finding the area under that curve, and there is more area under the xaxis than above.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right its symmetric and adds up to zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, sorry, you're right it's zero, I was just trying to explain how it could be negative. does it make sense now? sometimes, it's really helpful to look at a graph.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a force is just a vector, it can be negative, because it has magnitude & direction*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks, can i ask a quick question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just want to reiterate whats going on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0crap my browser froze
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