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anonymous

  • 5 years ago

I am really starting to loath this class that I am in! 6/(y-2) + 7/(y-8) = (y-1)/(y-8)

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  1. anonymous
    • 5 years ago
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    You will want to cancel out the terms in the denominator by multiplying everything by (y-2)(y-8). Hope that helps!

  2. anonymous
    • 5 years ago
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    kind of

  3. anonymous
    • 5 years ago
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    When you multiply through, (y-2) cancels out on the top and bottom of the first term and (y-8) cancels out on the other two leaving you with:\[6(y-8) + 7(y-2) = (y-1)(y-2)\]

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