A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

for the log quetsion. ln 1= 0 <-in this case, do i need to assume e is there? i can't remember the formulas, is there any way i can remember it?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ln 1 means to what power must you raise e to get 1.

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    does that make sense?

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea, I guess i am misunderstanding form of questions. can you help me out with more please?

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what are you having difficulty with?

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ln e = 1. i am confuse with the formulas

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is the 1 stands for? is power?

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, in that case it is the power of e.

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i.e. ln e ^10 = 10.

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ln and e are inverses of each other.

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    does that make sense?

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea, so that means above that example i show, ln e^1, is this right?

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for ln e = 1 is just saying that the log of the base itself, which is e, is 1.

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Exponential to Logarithmic: \[b^{x} = a\] I use b because b is the Base. B is for Base. \[\log_{b} (a) = x\] Fill in the blanks to change it to logarithmic using the numbers from the exponential form. Always remember, A Log Is an Exponent. A log with Base "e" is a special log which isnt written as \[\log_{e} a\] , but rather it is written as \[\ln a\]

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so in this case, In a, means log a without the base?

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\ln a \] means \[\log_{e} a\] , but it just is written as \[\ln a \]

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so for example, if ln 9, what is the answer going to be?

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Therefore when you have ln e = 1 you actually have: \[\log_{e} e = 1\] Which, if you convert it back to exponential form, you get: \[e ^{1} = e\]

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ln 9 = \[\log_{e} 9\] which can convert to \[e ^{x} = 9\]

  19. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for the exponent, is it possible to become a # instead of x ?

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ln 1=0 1 = e^0

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.