anonymous
  • anonymous
what is the derivative of -2(ln(3^4x))?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
factor out your constant: -2((d/dx)ln(3^(4x))) use the chain rule: ((dln(u))/du) (du/dx) where u = 3^(4x) use the chain rule again: ((d/dx) 3^4x (d3^u)/du (du/dx) where u = 4x factor out your constants: -2ln(3)(4(d/dx (x))) derivative of x = 1 d/dx(-2ln(3^(4x))) = -8ln(3)
anonymous
  • anonymous
thanks!! that is what I got, but my answer key says otherwise.
anonymous
  • anonymous
yeah, you may simplify it further, or may have simplified differently during an intermediate step

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