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anonymous
 5 years ago
y=x^22x15
how do you find the vertex?
anonymous
 5 years ago
y=x^22x15 how do you find the vertex?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the x intercepts are at 5 and 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0begin by completing the square

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to find the 'x' coordinate of the vertex, use x = b/2a or similarly take the first derivative, set equal to zero and solve for 'x'. To find the 'y' coord. just plug the 'x' value into the original equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, the 'x' intercepts are 5 and 3: (x+3)(x5) = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you complete the square you'll arrive at \[y=(x1)^{2}+13\] This is the standard form for a parabola. From this form, we then know that the vertex is at (1, 13)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i messed up haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=(x−1)2+14 so the vertex is at (1, 14)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0obviously the derivative thing isnt working for me ahha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that should work too. Take the first derivative: dy/dx=2x2 set the first derivative equal to zero: 2x2=0, x = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plug in x= 1 to the original equation to find the ycoordinate of the vertex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got the coordinates of the vertex to be (1,16)... After plugging in x=1. I may be wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but when i plug 1 in i get 16?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which is what i had the first time before i got confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y(1)=\[y(1) = 1^{2}2+15=14\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what you were doing wrong jjanelle haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, janelle, you got the 15 mixed up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can't read, good call.
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