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anonymous

  • 5 years ago

evaluate using product (x^2-1)^3*(x^2+2)

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  1. anonymous
    • 5 years ago
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    prouct rule?

  2. anonymous
    • 5 years ago
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    it sasys i can use product, quotient or chain???

  3. bahrom7893
    • 5 years ago
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    \[y = (x^2 - 1)^3 * (x^2+2)\]

  4. anonymous
    • 5 years ago
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    you got this bahrom! lol

  5. bahrom7893
    • 5 years ago
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    \[y' = (x^2-1)^3 \] \[y' = (x^2-1)^3*(2x) + (x^2+2)*3(x^2-1)^2*(2x)\]

  6. bahrom7893
    • 5 years ago
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    sorry ignore the first equation, i forgot to erase.

  7. bahrom7893
    • 5 years ago
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    \[y' = (x^2-1)^2 [2x(x^2-1) + 6x(x^2+2)]\]

  8. bahrom7893
    • 5 years ago
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    \[y' = (x^2-1)^2 2x[(x^2-1) + 3(x^2+2)]\]

  9. bahrom7893
    • 5 years ago
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    \[y' = 2x(x^2-1)^2 [(x^2-1) + 3(x^2+2)]\]

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