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anonymous

  • 5 years ago

Let f be the function with derivative given by f'(x)=x^2 - 2/x.Determine tje intervals on which f is decreasing.

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  1. anonymous
    • 5 years ago
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    find where f'(x) = 0. x² - 2/x = 0 x = 3sqrt(2) now plug in 2 values - greater than and less than 3sqrt(2) which ever is negative, is the decreasing one.

  2. anonymous
    • 5 years ago
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    x = 0 is also a critical number.

  3. anonymous
    • 5 years ago
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    O.o howd you get 0?

  4. bahrom7893
    • 5 years ago
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    banshee -2/x

  5. bahrom7893
    • 5 years ago
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    u need where the function doesn't exist too...

  6. anonymous
    • 5 years ago
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    oh rightttt doesnt exist xD touche!

  7. bahrom7893
    • 5 years ago
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    lol review ur calc...

  8. anonymous
    • 5 years ago
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    ; )

  9. anonymous
    • 5 years ago
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    Now im confuse somthing dnt add up

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