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anonymous

  • 5 years ago

simplify: x/(4) -1/(x) divided by 1/(2x)+1/4

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  1. bahrom7893
    • 5 years ago
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    \[(x/4 - 1/x)/[1/(2x) + 1/4]\]

  2. anonymous
    • 5 years ago
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    ok..

  3. anonymous
    • 5 years ago
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    x-2

  4. anonymous
    • 5 years ago
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    First multiply denominator and numerator by 4x. You will obtain (x^2 - 4)/(x+2)

  5. anonymous
    • 5 years ago
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    and then x+2 cancel out right?

  6. anonymous
    • 5 years ago
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    Expand the numerator to get (x+2)(x-2)/(x+2)

  7. anonymous
    • 5 years ago
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    Sure

  8. anonymous
    • 5 years ago
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    f(x)=1/27-3^x for which value is x undefined?

  9. anonymous
    • 5 years ago
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    When x is not equal to 3

  10. anonymous
    • 5 years ago
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    whenever the denominator equals zero, so at x = 3

  11. anonymous
    • 5 years ago
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    solve for x: log small 8 (x+1)=2/3

  12. anonymous
    • 5 years ago
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    Raise both sides to the 8

  13. bahrom7893
    • 5 years ago
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    sorry i had to leave... others helped anyway

  14. anonymous
    • 5 years ago
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    The cube root of 8 is 2; 2-squared is 4

  15. anonymous
    • 5 years ago
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    So , x+1 = 4

  16. anonymous
    • 5 years ago
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    x = 3

  17. anonymous
    • 5 years ago
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    write the full expansion of (3x+2)^4

  18. anonymous
    • 5 years ago
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    That may take a while. You know about pascal's triangle right?

  19. anonymous
    • 5 years ago
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    yeah i think i got the answer anyways i will give you another problem

  20. anonymous
    • 5 years ago
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    On a standardized test with a normal distribution, the mean was 64.3 and the standard deviation was 5.4. what percentile is a 74?

  21. anonymous
    • 5 years ago
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    I'm a lil rusty with statistics. I'll look up a formula and do it, but post it to see if others can help with it aite

  22. anonymous
    • 5 years ago
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    Between what two values does 68.2% of the distribution lie?

  23. anonymous
    • 5 years ago
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    You have any problems not related to statistics? Or these are the only ones?

  24. anonymous
    • 5 years ago
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    these are the only ones

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