anonymous
  • anonymous
asking to use the implicit differentiation to find dy/dx of 2xy-y^2=1
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
first: 2y+2xy'-2yy'=0 Next, solve for y': y' = -2y/(2x-2y)
anonymous
  • anonymous
the answer should be y/y-x .. can u explain step by step if you get this answer.
anonymous
  • anonymous
yes, that is just simplifying -2y/(2x-2y)

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anonymous
  • anonymous
factor a -2 out of the numerator and denominator: -2(y)/[-2(y-x)]=y/(y-x)
anonymous
  • anonymous
thank jjanelle.. ur great

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