anonymous
  • anonymous
f(x)=(3x^2-2x-1) find equation of the line that is tangent and parallel to this line 8x-2y+12=0
Mathematics
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anonymous
  • anonymous
f(x)=(3x^2-2x-1) find equation of the line that is tangent and parallel to this line 8x-2y+12=0
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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bahrom7893
  • bahrom7893
wait to which line? f(x)=(3x^2-2x-1) or 8x-2y+12=0?
anonymous
  • anonymous
8x-2y+12=0 cant figure it out because i need the two points (x and Y) my book is not clear
anonymous
  • anonymous
howdy. First we can find the slope of the line. I'll rewrite it in y=mx+b form to make it apparent: y = 4x+6 -> slope is 4

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anonymous
  • anonymous
Then we need to find where the derivative (slope of the tangent) is equal to 4
anonymous
  • anonymous
The derivative is: f'(x)=6x-2 4=6x-2 -> x = 1
anonymous
  • anonymous
This means that the tangent line to f(x) at x = 1 has a slope of 4 and is thus parallel to the given line. Now we just need to find f(1) to write the equation of a line: y(1) = 3(1^2)-2(1)-1=0
anonymous
  • anonymous
Thus the line is: y = 4(x-1) + 0 = 4x-4
anonymous
  • anonymous
thank you very helpful

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