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anonymous
 5 years ago
f(x)=(3x^22x1) find equation of the line that is tangent and parallel to this line 8x2y+12=0
anonymous
 5 years ago
f(x)=(3x^22x1) find equation of the line that is tangent and parallel to this line 8x2y+12=0

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0wait to which line? f(x)=(3x^22x1) or 8x2y+12=0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.08x2y+12=0 cant figure it out because i need the two points (x and Y) my book is not clear

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0howdy. First we can find the slope of the line. I'll rewrite it in y=mx+b form to make it apparent: y = 4x+6 > slope is 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then we need to find where the derivative (slope of the tangent) is equal to 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative is: f'(x)=6x2 4=6x2 > x = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This means that the tangent line to f(x) at x = 1 has a slope of 4 and is thus parallel to the given line. Now we just need to find f(1) to write the equation of a line: y(1) = 3(1^2)2(1)1=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thus the line is: y = 4(x1) + 0 = 4x4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you very helpful
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