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derivate 3t(sint/t-t^2/3)

Mathematics
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\[3t*((\sin t)/(t- t ^{2/3}))\] Is this the question?
i need to find the derivate
I know, I want to know if I wrote the question correctly.

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Other answers:

yes :=)
Okay. Its quite trivial, but tedious. Its easy to make mistakes in this. Do you just want the answer to verify your answer or do you need explanation also?
yes i want the answer please i want to verify if with mine these derivates are driving me crazy
wait the question is wrong
okay
3t((sint/t)-t^2/3))
3T(sin t divided by t and t^2 divided by 3)
aite cool
Well. This problem looks alot less tedious than before. Just distribute the 3t and you'll get: 3sin(t) - t^3 When you take its derivative you'll get: 3cos(t) - 3t^2
i got 3cos(T)-9T^2 the 9 from multiplying 3t(t^2/3) dont know ;-(

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