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anonymous

  • 5 years ago

derivate 3t(sint/t-t^2/3)

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  1. anonymous
    • 5 years ago
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    \[3t*((\sin t)/(t- t ^{2/3}))\] Is this the question?

  2. anonymous
    • 5 years ago
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    i need to find the derivate

  3. anonymous
    • 5 years ago
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    I know, I want to know if I wrote the question correctly.

  4. anonymous
    • 5 years ago
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    yes :=)

  5. anonymous
    • 5 years ago
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    Okay. Its quite trivial, but tedious. Its easy to make mistakes in this. Do you just want the answer to verify your answer or do you need explanation also?

  6. anonymous
    • 5 years ago
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    yes i want the answer please i want to verify if with mine these derivates are driving me crazy

  7. anonymous
    • 5 years ago
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    wait the question is wrong

  8. anonymous
    • 5 years ago
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    okay

  9. anonymous
    • 5 years ago
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    3t((sint/t)-t^2/3))

  10. anonymous
    • 5 years ago
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    3T(sin t divided by t and t^2 divided by 3)

  11. anonymous
    • 5 years ago
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    aite cool

  12. anonymous
    • 5 years ago
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    Well. This problem looks alot less tedious than before. Just distribute the 3t and you'll get: 3sin(t) - t^3 When you take its derivative you'll get: 3cos(t) - 3t^2

  13. anonymous
    • 5 years ago
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    i got 3cos(T)-9T^2 the 9 from multiplying 3t(t^2/3) dont know ;-(

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