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anonymous

  • 5 years ago

how do i find the anti derivative of 9-4x^2 all raised to 1/2

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  1. anonymous
    • 5 years ago
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    first raise everything to the (1/2) power. 9^(1/2) - 4^(1/2)(x^2)^(1/2) and get 3 - 2x.

  2. anonymous
    • 5 years ago
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    apparently i need to use the table of integrals and it says perhaps one substitutions

  3. anonymous
    • 5 years ago
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    ok would that be finding the perfect square?

  4. anonymous
    • 5 years ago
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    yeah theyre all perfect squares. its easy to get the anti derivative now

  5. anonymous
    • 5 years ago
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    how do i do it with table of integrals?

  6. anonymous
    • 5 years ago
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    the table is just all the rules for finding the anti derivative aka integral

  7. anonymous
    • 5 years ago
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    \[\sqrt{9-4x^2}\] fits into square root of a^2 +or- x^2 but laves 1 over the square root of a^2-x^2 to still be found

  8. anonymous
    • 5 years ago
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    i cant get it to fit into any other equation

  9. anonymous
    • 5 years ago
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    sorry i wasnt looking at it right http://www.wolframalpha.com/input/?i=integral+%289-4x^2%29^%281%2F2%29

  10. anonymous
    • 5 years ago
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    copy the whole thing dont click

  11. anonymous
    • 5 years ago
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    k

  12. anonymous
    • 5 years ago
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    how do i tell what equations it used though?

  13. anonymous
    • 5 years ago
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    ok i see thank you so much!!!!!!!!!

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spraguer (Moderator)
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