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anonymous
 5 years ago
For which values of t does the following homogeneous linear system have nontrivial solutions?
12x1x2+x3=0
tx1 +x3=0
x2+tx3=0
anonymous
 5 years ago
For which values of t does the following homogeneous linear system have nontrivial solutions? 12x1x2+x3=0 tx1 +x3=0 x2+tx3=0

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0coefficient matrix = 12, 1, 1; 1,0,1; 0,1,1... augmented matrix = 12,1, 1,0; 1,0,1,0; 0,1,1,0.... RREF> gives identity matrix, so they are all liniar independent...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0linearly* independent...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, but how do you get the tvalue?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are no tvalues, this is not a dependent system, it is inconssistent, the only solution is the trivial solution (0,0,0)...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, do you mean the t in front of the x1 at r2,c1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are actually two t's the other one at r3,c3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(I'm in the same class so we're learning about this, so I'm curious as to how to solve this too).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, sorry, misread it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know t = 4 or 3 from the back of the book

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, i may nead a second...if that's ok...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this your first semester of linear algebra?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You learn how to turn that system into matrix right? It is easier if you did. With that technique you will end up with t(1+t)12 to get nontrivial solution, that expression must not equal to 0 so you just solve \[t(1+t)12\neq0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so that is a row in your matrix?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes one row ended up to be [0 0 t(1+t)12 0]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok perfect, thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Cool! I actually got that once I pulled out my whiteboard and tried to do row echelon form. Thanks guys!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey quantish you should post more linear algebra problems so it forces me to study. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha, you should talk to applekiwi...the solution that I was working on was more backward and difficult ; )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have a test coming up and even though I look over the material in the chapters, make flashcards full of definitions and theorems, and try to pratice and review problems, I am very slow.
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