Trig question: I am being asked to graph one period ending with x=2 pi. I I have graphed it (with no graphing calculator) and do not understand the solution at the end of my book. I think the y min. and y max. should by 1 and -1. Why does the book say it is 1.2 and -1.2?
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Hmmm. Off the top of my head, I would say you are right. What was the equation you were asked to graph one period of?
y=cosx - Graph one period ending at x=2Pi.
The book asks to record xmin,max,scl & y min, max, scl.
First time I have taken Trig. Just trying to figure out why this is 1.2 and not 1?
Well, the book could be wrong, couldn't it? The maximum value of the cosine curve is 1. No question about it. And the minimum value of cosine is -1.
Ahh ... I think the book is giving you the y min and y max of the calculator's WINDOW, not the y min and y max of the curve itself. That would give a little margin around the curve. Does that make work for you? (That IS what the TI calculator window calls the vertical scale.)