Find the linear approximation of f(x)=sqrt (16-x) at a=0 and use it to approximate sqrt (15.9) and sqrt(16.1)

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Find the linear approximation of f(x)=sqrt (16-x) at a=0 and use it to approximate sqrt (15.9) and sqrt(16.1)

Mathematics
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again?
L(x) = f(a) + f'(a) (x-a)
f'(x) = (1/2) (16-x)^(-1/2) * (-1)

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wait let me put this in neater format
i get that part...need help wit second half
oh okay so to approximate..
what did u get for the result for L(x) ? So that I don't have to work it out again
im at sqrt (16-x)+1/2(16-x)^-1/2
So in this case to approximate: sqrt(15.9) is approximately f(16) + f'(16) * (16-15.9)
sorry no
sqrt(15.9) is approximately f(16) + f'(16) * (15.9-16)
wait sorry i got lost let me work on this on my own..
carra u here? i got it... gotta go somewhere else to explain though, can we go on twiddla?
http://www.twiddla.com/496311

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