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anonymous

  • 5 years ago

Find the linear approximation of f(x)=sqrt (16-x) at a=0 and use it to approximate sqrt (15.9) and sqrt(16.1)

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  1. bahrom7893
    • 5 years ago
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    again?

  2. bahrom7893
    • 5 years ago
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    L(x) = f(a) + f'(a) (x-a)

  3. bahrom7893
    • 5 years ago
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    f'(x) = (1/2) (16-x)^(-1/2) * (-1)

  4. bahrom7893
    • 5 years ago
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    wait let me put this in neater format

  5. anonymous
    • 5 years ago
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    i get that part...need help wit second half

  6. bahrom7893
    • 5 years ago
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    oh okay so to approximate..

  7. bahrom7893
    • 5 years ago
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    what did u get for the result for L(x) ? So that I don't have to work it out again

  8. anonymous
    • 5 years ago
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    im at sqrt (16-x)+1/2(16-x)^-1/2

  9. bahrom7893
    • 5 years ago
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    So in this case to approximate: sqrt(15.9) is approximately f(16) + f'(16) * (16-15.9)

  10. bahrom7893
    • 5 years ago
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    sorry no

  11. bahrom7893
    • 5 years ago
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    sqrt(15.9) is approximately f(16) + f'(16) * (15.9-16)

  12. bahrom7893
    • 5 years ago
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    wait sorry i got lost let me work on this on my own..

  13. bahrom7893
    • 5 years ago
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    carra u here? i got it... gotta go somewhere else to explain though, can we go on twiddla?

  14. bahrom7893
    • 5 years ago
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    http://www.twiddla.com/496311

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