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anonymous
 5 years ago
find derivate (3x^3)  (8x^3/4/3)  (3/x^3)
anonymous
 5 years ago
find derivate (3x^3)  (8x^3/4/3)  (3/x^3)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not quite sure what the second term is... (8x³/4)/3 or 8x³/(4/3) there's a difference... anyway, for the first term, power rule  9x² for the third term, bring the x³ to make it 3x^3 power rule again 9x^4 aka 9/(x^4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, first term is not negative lol just 9x²...third term is negative though lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i know thank you but the second is 8X^3/4 DIVIDED BY 3 AND THE LAST TERM IS 3/X^3 WHICH IS 3X^3 RIGHT

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, second term is (8x³/4)/3 rewrite as 8x³/12. if you look at it, its just like saying (8/12) times x³ so you could apply the power rule (almost pretending the 8/12 is just another easy whole number) so you'd get (24/12)x² and yes, the last term u bring the x³ up to x^3. then apply power rule :) You got this!
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