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anonymous
 5 years ago
use the echelon method to solve the following system of three equations
5x2y+5z=59
3x2y3z=1
xy+2z=12
anonymous
 5 years ago
use the echelon method to solve the following system of three equations 5x2y+5z=59 3x2y3z=1 xy+2z=12

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey sorry for not responding sooner (it takes me a while to do these). Anyway I would first set up the matrix like so: [5 2 559] [3 2 31] [1 1 212] If you swap the first with the third row you have this: [1 1 212] [3 2 31] [5 2 559] Next let your new Row2=row23*(row1) and let your new Row 3 = row35*(row1). Then you will have: [1 1 212] [0 1 937] [0 3 51] Next make your new Row3=row33*(row2). Then you should have: [1 1 212] [0 1 937] [0 0 22110] Then for your new Row3 multiply 1/22 with your old row3. So you have: [1 1 212] [0 1 937] [0 0 1 5] Now you have enough information to solve the system of equations. z=5 y9z=37 xy+2z=12 I leave it to you to finish. :D Did that help?
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