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anonymous
 5 years ago
use implicit differentiation to find dy/dx  2xyy^2= 1 can someone explain step by step with formulas explaining in detail.
anonymous
 5 years ago
use implicit differentiation to find dy/dx  2xyy^2= 1 can someone explain step by step with formulas explaining in detail.

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bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0Let me call dy/dx y'

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0use product rule for 2xy and power rule for y^2: 2x*y' + y*(2)  2y*y' = 0

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.02xy'  2y  2yy' = 0, divide everything by 2: xy' + y + yy' = 0

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0now move y to the right side: xy' + yy' = y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02xyy^2 = 1 is original problem right?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, but derivative of a constant is 0!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the formula for implicit differentiation ?

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0now move y to the right side: xy' + yy' = y take y' out: y'(x+y) = y

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0there is no formula, u use a combination of several formulas

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ah...ok let me look and little by little look into what u wrote to understand

bahrom7893
 5 years ago
Best ResponseYou've already chosen the best response.0y' = dy/dx = y/(x+y). Fan me if I helped, thanx! =)
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