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anonymous
 5 years ago
if a ball is thrown into the air with a velocity of 40ft/s, its height in feet t seconds later is given by y=40t16t^2. find the average velocity for the time period beginning when t=2 and lasting 0.5 seconds
anonymous
 5 years ago
if a ball is thrown into the air with a velocity of 40ft/s, its height in feet t seconds later is given by y=40t16t^2. find the average velocity for the time period beginning when t=2 and lasting 0.5 seconds

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = the upward distance = 40t  16t^2 distance/time = velocity Let V be the velocity so V = y /t = 40  16 t, t = 2 V = 40  32 = 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is the equation y=40t16t^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did u plug t=2 and (0.5)seconds

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, y = 40t  16t^2 y /t is velocity = 40  16t st t = 2, v = 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Vavg = (yfyi)/(tfti) yf = 40(2.5)16(2.5)^2 = 0 yi = 40(2)16(2)^2 = 16 tf = 2.5 ti = 2 Vavg = (016)/(2.52) = 16/.5 = 32 ft/s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The problem asked for AVERAGE velocity from t=2 and lasting .5 seconds, so the initial time is t=2 and the final time is t=2.5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok how did u get 2.5 u added then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, if you start at t=2 and end .5 seconds later, then the final time is t=2.5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p.kanan found the velocity when t=2, which is not the average velocity from t=2 to t=2.5 as the problem asked.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you understand? there is a difference between average velocity and velocity at a certain instant.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sip another qs. in the denominator is no supose to be 40(2)16(0.5)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I really don't understand what you're asking. what denominator? your change in time i.e. time final  time initial belongs in the denominator if you're are finding Vavg.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Change in position i.e. y final  y initial belongs in the numerator.
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