anonymous
  • anonymous
okay really confused now!!! 31^2=square root of 177+b^2????? huh???!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Is this the original problem?
anonymous
  • anonymous
yes I typed it right from the book were working
anonymous
  • anonymous
Ok

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anonymous
  • anonymous
So what is 31^2?
anonymous
  • anonymous
31^2=961 961-177 = 784 sqrt(784)=28 b=28
anonymous
  • anonymous
Then once you figure that out, set both sides to the power of 2 , to get rid of the sqrt sign
anonymous
  • anonymous
Lol, ^ what he said then.
anonymous
  • anonymous
lol ok
anonymous
  • anonymous
Wait hold on.. is the 177+b^2 all inside the parenthesis? or seperate?
anonymous
  • anonymous
ok, sunshine, do you know what Pythagorean theorem is used for?
anonymous
  • anonymous
Is the problem like this \[31^2 = \sqrt(177)+b^2 or 31^2=\sqrt(177+b^2)\]
anonymous
  • anonymous
but don't you square root the 177 first???
anonymous
  • anonymous
Depends. That is why you need to tell me which one the book is saying. Is 177 the only number inside the square root?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay based on what you said the problem is it is similar to what bpw12 did: 31^2=961 961-sqrt177 = 947.696 b= sqrt(947.696)=30.785 b=28
anonymous
  • anonymous
ok ill retype the problem exactly [31^2=sqrt{177}+b^2
anonymous
  • anonymous
Yeah, then it is what I said to do then.
anonymous
  • anonymous
ok do i square root the 177 at the end???
anonymous
  • anonymous
Nope. After you subtract sqrt {177} from both sides you have: 31^2-sqrt{177}=b^2 947.696=b^2 sqrt(947.696)=sqrt(b^2) Now you may or may not learned this next part, but technically there will be two solutions for b now that I think about (sorry mind is being slow tonight). So b=30.785 or b=-30.785 P.S. Ignore the b=28 from my post from like 8 minutes ago
anonymous
  • anonymous
ok I'm skipping this prob ill ask my teacher tomorrow

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