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anonymous

  • 5 years ago

okay really confused now!!! 31^2=square root of 177+b^2????? huh???!!!

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  1. anonymous
    • 5 years ago
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    Is this the original problem?

  2. anonymous
    • 5 years ago
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    yes I typed it right from the book were working

  3. anonymous
    • 5 years ago
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    Ok

  4. anonymous
    • 5 years ago
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    So what is 31^2?

  5. anonymous
    • 5 years ago
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    31^2=961 961-177 = 784 sqrt(784)=28 b=28

  6. anonymous
    • 5 years ago
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    Then once you figure that out, set both sides to the power of 2 , to get rid of the sqrt sign

  7. anonymous
    • 5 years ago
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    Lol, ^ what he said then.

  8. anonymous
    • 5 years ago
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    lol ok

  9. anonymous
    • 5 years ago
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    Wait hold on.. is the 177+b^2 all inside the parenthesis? or seperate?

  10. anonymous
    • 5 years ago
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    ok, sunshine, do you know what Pythagorean theorem is used for?

  11. anonymous
    • 5 years ago
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    Is the problem like this \[31^2 = \sqrt(177)+b^2 or 31^2=\sqrt(177+b^2)\]

  12. anonymous
    • 5 years ago
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    but don't you square root the 177 first???

  13. anonymous
    • 5 years ago
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    Depends. That is why you need to tell me which one the book is saying. Is 177 the only number inside the square root?

  14. anonymous
    • 5 years ago
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    yes

  15. anonymous
    • 5 years ago
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    Okay based on what you said the problem is it is similar to what bpw12 did: 31^2=961 961-sqrt177 = 947.696 b= sqrt(947.696)=30.785 b=28

  16. anonymous
    • 5 years ago
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    ok ill retype the problem exactly [31^2=sqrt{177}+b^2

  17. anonymous
    • 5 years ago
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    Yeah, then it is what I said to do then.

  18. anonymous
    • 5 years ago
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    ok do i square root the 177 at the end???

  19. anonymous
    • 5 years ago
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    Nope. After you subtract sqrt {177} from both sides you have: 31^2-sqrt{177}=b^2 947.696=b^2 sqrt(947.696)=sqrt(b^2) Now you may or may not learned this next part, but technically there will be two solutions for b now that I think about (sorry mind is being slow tonight). So b=30.785 or b=-30.785 P.S. Ignore the b=28 from my post from like 8 minutes ago

  20. anonymous
    • 5 years ago
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    ok I'm skipping this prob ill ask my teacher tomorrow

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