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okay really confused now!!! 31^2=square root of 177+b^2????? huh???!!!

Mathematics
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Is this the original problem?
yes I typed it right from the book were working
Ok

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Other answers:

So what is 31^2?
31^2=961 961-177 = 784 sqrt(784)=28 b=28
Then once you figure that out, set both sides to the power of 2 , to get rid of the sqrt sign
Lol, ^ what he said then.
lol ok
Wait hold on.. is the 177+b^2 all inside the parenthesis? or seperate?
ok, sunshine, do you know what Pythagorean theorem is used for?
Is the problem like this \[31^2 = \sqrt(177)+b^2 or 31^2=\sqrt(177+b^2)\]
but don't you square root the 177 first???
Depends. That is why you need to tell me which one the book is saying. Is 177 the only number inside the square root?
yes
Okay based on what you said the problem is it is similar to what bpw12 did: 31^2=961 961-sqrt177 = 947.696 b= sqrt(947.696)=30.785 b=28
ok ill retype the problem exactly [31^2=sqrt{177}+b^2
Yeah, then it is what I said to do then.
ok do i square root the 177 at the end???
Nope. After you subtract sqrt {177} from both sides you have: 31^2-sqrt{177}=b^2 947.696=b^2 sqrt(947.696)=sqrt(b^2) Now you may or may not learned this next part, but technically there will be two solutions for b now that I think about (sorry mind is being slow tonight). So b=30.785 or b=-30.785 P.S. Ignore the b=28 from my post from like 8 minutes ago
ok I'm skipping this prob ill ask my teacher tomorrow

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