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- anonymous

ok now it's a geometry story problem

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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- anonymous

ok now it's a geometry story problem

- katieb

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- anonymous

angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of

- anonymous

angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

- anonymous

Okay this is where Pythagorean theorem comes in handy.
So AB will be the hypotensue of your triangle and AC is one of the sides.
So c^2=a^2+b^2
We substitute our hypothenuse for c and our side for either a or b (it does not matter which one).
So 17^2=8^2+b^2
Then solve for b. Let me know what you get. :D

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- anonymous

yaaay! you kinda taught her Pythagorean theorem

- anonymous

(mathfreak, we talked about this, cool it)

- anonymous

LOL

- anonymous

ok so b=225???

- anonymous

That is b^2=225. So you have one more step. :D

- anonymous

oh square root 225?

- anonymous

Which is?

- anonymous

15=b?

- anonymous

Yep!

- anonymous

so 15 is the measure of angle BC?

- anonymous

Angle BC???? I thought it was the length BC.

- anonymous

UGH

- anonymous

- anonymous

Stick with what you have, then. BC is not an angle, neither was AB or AC.

- anonymous

lol ok

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