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anonymous
 5 years ago
ok now it's a geometry story problem
anonymous
 5 years ago
ok now it's a geometry story problem

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay this is where Pythagorean theorem comes in handy. So AB will be the hypotensue of your triangle and AC is one of the sides. So c^2=a^2+b^2 We substitute our hypothenuse for c and our side for either a or b (it does not matter which one). So 17^2=8^2+b^2 Then solve for b. Let me know what you get. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yaaay! you kinda taught her Pythagorean theorem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(mathfreak, we talked about this, cool it)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is b^2=225. So you have one more step. :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 15 is the measure of angle BC?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Angle BC???? I thought it was the length BC.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Stick with what you have, then. BC is not an angle, neither was AB or AC.
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