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anonymous

  • 5 years ago

ok now it's a geometry story problem

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  1. anonymous
    • 5 years ago
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    angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of

  2. anonymous
    • 5 years ago
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    angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

  3. anonymous
    • 5 years ago
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    Okay this is where Pythagorean theorem comes in handy. So AB will be the hypotensue of your triangle and AC is one of the sides. So c^2=a^2+b^2 We substitute our hypothenuse for c and our side for either a or b (it does not matter which one). So 17^2=8^2+b^2 Then solve for b. Let me know what you get. :D

  4. anonymous
    • 5 years ago
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    yaaay! you kinda taught her Pythagorean theorem

  5. anonymous
    • 5 years ago
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    (mathfreak, we talked about this, cool it)

  6. anonymous
    • 5 years ago
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    LOL

  7. anonymous
    • 5 years ago
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    ok so b=225???

  8. anonymous
    • 5 years ago
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    That is b^2=225. So you have one more step. :D

  9. anonymous
    • 5 years ago
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    oh square root 225?

  10. anonymous
    • 5 years ago
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    Which is?

  11. anonymous
    • 5 years ago
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    15=b?

  12. anonymous
    • 5 years ago
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    Yep!

  13. anonymous
    • 5 years ago
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    so 15 is the measure of angle BC?

  14. anonymous
    • 5 years ago
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    Angle BC???? I thought it was the length BC.

  15. anonymous
    • 5 years ago
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    UGH

  16. anonymous
    • 5 years ago
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    angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.

  17. anonymous
    • 5 years ago
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    Stick with what you have, then. BC is not an angle, neither was AB or AC.

  18. anonymous
    • 5 years ago
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    lol ok

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