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ok now it's a geometry story problem

Mathematics
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angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of
angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.
Okay this is where Pythagorean theorem comes in handy. So AB will be the hypotensue of your triangle and AC is one of the sides. So c^2=a^2+b^2 We substitute our hypothenuse for c and our side for either a or b (it does not matter which one). So 17^2=8^2+b^2 Then solve for b. Let me know what you get. :D

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Other answers:

yaaay! you kinda taught her Pythagorean theorem
(mathfreak, we talked about this, cool it)
LOL
ok so b=225???
That is b^2=225. So you have one more step. :D
oh square root 225?
Which is?
15=b?
Yep!
so 15 is the measure of angle BC?
Angle BC???? I thought it was the length BC.
UGH
angle ABC is an inscribed right angle. If the measure of AB is 17 and the measure of AC is 8, find the measure of BC.
Stick with what you have, then. BC is not an angle, neither was AB or AC.
lol ok

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