A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
if in a graph the lim f(x) when x is approaching to 1 is equal to 1 because 1 is included on the graph when the lim f(x) when x approach to 1+, but is this graph 1 is not included what will be the limit
anonymous
 5 years ago
if in a graph the lim f(x) when x is approaching to 1 is equal to 1 because 1 is included on the graph when the lim f(x) when x approach to 1+, but is this graph 1 is not included what will be the limit

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so, you're saying the limit as x approaches 1+ does not exist? If the left and right limits at a point are not equal, then the limit does not exist.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well that is what i want to know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In better notation, if \[\lim_{x \rightarrow 1+}\neq \lim_{x \rightarrow 1}\] then the limit does not exist

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the ask me to find the limit f(x) x>1 lim f(x) x>1+ lim f(x) x>1 so where does the limit exist if from left to right 1 is include but from right to left is not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the limit from the left exists, but the limit from the right and at 1 dne

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a graph to accompany this? The right limit could still exist. the limit at 1 does not exist

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0perfect in order for the lim of the 1 + exist must exist from both site
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.