anonymous
  • anonymous
The Earth's orbit around the sun is elliptical, with the center of the sun at one focus. The length of the major axis is 186 million miles and the two foci are 3.2 million miles apart. What is the length of the minor axis of the ellipse?
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
By my calculation, the length of the minor axis is 185.9931182. I got this number by using the formula for calculating the focal length of an ellipse, which is \[a ^{2}-b ^{2}=c ^{2}\]. Rearranging this formula to make use of my known data (that A=186 and C=1.6 [remember, the focal length will be HALF of the distance between the foci]) I get \[186^{2}-b ^{2}=1.6^{2}\]. Solving for b, I get \[\sqrt{186^{2}-1.6^{2}}\], which is approximately 185.9931182.

Looking for something else?

Not the answer you are looking for? Search for more explanations.