I can't find critical points for y=x(9-x^2)^1/2

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I can't find critical points for y=x(9-x^2)^1/2

Mathematics
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First take the derivative dy/dx=\[(9-2x ^{2})/\sqrt{9-x ^{2}}\]
next we must find where dy/dx = 0 or where it is undefined
dy/dx = 0 for \[x = \pm \sqrt{9/2}\]

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Other answers:

dy/dx is undefined for \[x = \pm3\], when the denominator equals 0
Are you looking for a specific type of critical point?
\[y = x \sqrt{9-x^2}\] the derivative of it is: \[y'=\sqrt{9-x^2} -x^2/\sqrt{9-x^2}\] then y'=0 finely x =2.45
that is not the only answer.
and the derivative is not quite correct.
The critical points should be \[x = \pm \sqrt{9/2}\]
oops, sorry corec, the derivative is fine

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