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anonymous
 5 years ago
I can't find critical points for y=x(9x^2)^1/2
anonymous
 5 years ago
I can't find critical points for y=x(9x^2)^1/2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First take the derivative dy/dx=\[(92x ^{2})/\sqrt{9x ^{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0next we must find where dy/dx = 0 or where it is undefined

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx = 0 for \[x = \pm \sqrt{9/2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx is undefined for \[x = \pm3\], when the denominator equals 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you looking for a specific type of critical point?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = x \sqrt{9x^2}\] the derivative of it is: \[y'=\sqrt{9x^2} x^2/\sqrt{9x^2}\] then y'=0 finely x =2.45

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is not the only answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the derivative is not quite correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The critical points should be \[x = \pm \sqrt{9/2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops, sorry corec, the derivative is fine
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