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anonymous
 5 years ago
how do u find the equation of the tangent line to the curve at the given point:
y=e^x/x, (1,e)
anonymous
 5 years ago
how do u find the equation of the tangent line to the curve at the given point: y=e^x/x, (1,e)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. Take its derivative: \[dy/dx = e ^{x}/x ^{2} + e ^{x}/x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Whatever value you obtain for dy/dx after the substitution, let that represent your m value for the equation y = mx+c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got 0 as the slope but then when i plug it in i still get the wrong answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To solve for the constant 'c', just substitute: x = 1 y = e m =dy/dx (Its numerical value that you obtained) Then, for your final sub in the c and m values

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Double check to make sure my derivative is correct

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But i'm quite sure the steps are correct though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Using the derivative presented above, I also get 0 as it's derivative at x=1. If this is the case then the equation of the tangent line at the point (1,e) on the original curve should be y=e.
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