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anonymous
 5 years ago
Find the zeros of the function x^2  x4
anonymous
 5 years ago
Find the zeros of the function x^2  x4

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shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to factor this equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes but my problem is, is that I can't think of anything that added toger is 1 and multi to get 4

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Hm. Fair enough. So there are a couple of ways to approach this. Do you know the quadratic formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes 2 + \[b +_\sqrt{b^2  4ac} \over 2a\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Right. Do you know what a, b, and c are in your equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes a is 1x^2 b is 1x and c is 4

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Close, a, b, and c are the coefficients  so a is 1, b is 1, and c is 4. Remember that a minus sign is part of the coefficient :) Can you plug those in?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I get \[1 \pm \sqrt{15} \over 2\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Righto. And there are your two zeros.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what are the two zeros?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0The quadratic equation describes two results: \[x = \frac{1 + \sqrt{15}}{2}\] and \[x = \frac{1  \sqrt{15}}{2}\] Those are the two zeros of the equation.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0No problem, glad to help :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't this be 17 instead of 15?
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