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the average of n numbers: (n1 + n2 + n3 + ... nn) / n
ie:
\[\frac{\sum_{i=1}^{n}n_i}{n}\]

\[\frac{(23 + 18 + 16 + 24 + 27 + x)}{6} = 20\]
now we solve for x

108 + x = 20 * 6

x = 120 - 108 = 12.

so we know in his 6th game he scored 12 points.

Thank you, but how did you know to subtract? do you do the opposite when you flip the equation over

thank you so much,