A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
what is the derivative of 5cos^2(pi)(t)?
anonymous
 5 years ago
what is the derivative of 5cos^2(pi)(t)?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i assume you mean 5cos^2((pi*t)) in which case; i would use the chain rule, subs u=cos(pi*t), so you have (i presume it's y), y=5u^2 dy/du = 10u and du/dt=pi*sin(pi*t) Multiply them together, dy/dx = 10u * pi*sin(pi*t) replace u=cos(pi*t) dy/dx=10*pi*cos(pi*t)*sin(pi*t) And you could then use the relation that sin(2x)=2sin(x)cos(x) so dy/dx=5*pi*sin(2*pi*t) You could alternatively use the relation that 2cos(2x)=cos^2(x)+1 and rearrange for cos^2(x) [x being pi*t] .. which is a better way if you know how to do it .. hope this helps :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.