## anonymous 5 years ago how do you find critical number in calculus

1. anonymous

$\sqrt{2-x}$

2. anonymous

Take the derivative with respect to x, then find where the derivative is 0 or undefined

3. anonymous

$d/dx[\sqrt{2-x}] = -1/(2\sqrt{2-x})$

4. anonymous

The derivative can never be zero, so we need to next find if there is a point where it is undefined

5. anonymous

in this case, at x = 2

6. anonymous

This is a vertical tangent to the function

7. anonymous

thanks