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anonymous

  • 5 years ago

second derivative of 4(x^2-2)^3

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  1. anonymous
    • 5 years ago
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    right, i presume u've seen before that you can derive an equation of the form (ax+b)^n, and the answer would be an(ax+b)^(n-1), when you have a higher order polynomial of this form (ax^2+b)^n, you do the chain rule .. u=ax^2+b .. and so on .. there is a quick way to do it in you head which is, write down the bracket, multiply it by the power times by the derivative of what's in the bracket, so in the general case, 2axn(ax^2+b)^(n-1), so for you; y=4(x^2-2)^3 dy/dx= 4*2x*3(x^2-2)^2 dy/dx=24x(x^2-2)^2 you now do it again to get the second derivative, see if you can do it .. hope this helps and it's not too basic and long winded

  2. anonymous
    • 5 years ago
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    the first derivative wasnt the hard part. i already did the chain rule and got the first derivative. i just cant get the second

  3. anonymous
    • 5 years ago
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    because you have to do the power rule and the chain rule for f"

  4. anonymous
    • 5 years ago
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    no just do the same exact thing again like i've shown you above

  5. anonymous
    • 5 years ago
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    96x^2(x^2-2) ??

  6. anonymous
    • 5 years ago
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    yh tht's it

  7. anonymous
    • 5 years ago
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    sweeet thanks

  8. anonymous
    • 5 years ago
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    nws anytime

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