Factor 4x^2-4x+1 show all work please im trying to get this down.

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Factor 4x^2-4x+1 show all work please im trying to get this down.

Mathematics
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ok this equation doesn't factor by the most basic of method, have you tried using complete the square, cause that would work
no how would you do that? is there a way that works on all of them?
usually it will tell you how to do it i'll show you the complete the square method if you'd like

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is that definitely what the question says??
it says factor completly the it shows \[4x^2-4x+1\]
ok well firstly i'm gonna divide by 4 so there's no coefficient of x^2, this gives, x^2-x+1/4 (you can see that this would equal (x-1/2)^2 (i can see an answer from here but i'd like to show you the complete the square method as it is used a lot later on) Right, if you have a quadratic of the form x^2+bx+c, you can write it as; (x+b/2)^2-((b/2)^2)+c, so in your case; (x-1/2)^2-(-1/2)^2+1/4 (-1/2)^2 = 1/4 (x-1/2)^2+1/4-1/4 (x-1/2)^2 is your factorised equation

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