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anonymous

  • 5 years ago

whats the integral of lnt/t

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  1. anonymous
    • 5 years ago
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    You can solve this using u-substitution. let u = Ln(t) so du = 1/t dt

  2. anonymous
    • 5 years ago
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    The problem then becomes \[\int\limits_{?}^{?}u du = u ^{2}/2 + c = (Ln(t))^{2}/2 + c\]

  3. anonymous
    • 5 years ago
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    \[\int\limits_{1}^{e}\]

  4. anonymous
    • 5 years ago
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    You need the integral from 1 to e?

  5. anonymous
    • 5 years ago
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    yes evalute

  6. anonymous
    • 5 years ago
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    you should try it from here

  7. anonymous
    • 5 years ago
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    ok.. thanks

  8. anonymous
    • 5 years ago
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    Ln(1)^2 - Ln(e)^2

  9. anonymous
    • 5 years ago
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    oops, sorry. Ln(e)^2-Ln(1)^2

  10. anonymous
    • 5 years ago
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    then divide the answer by 2

  11. anonymous
    • 5 years ago
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    ln|1| is 0 right

  12. anonymous
    • 5 years ago
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    yes

  13. anonymous
    • 5 years ago
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    the answer is 1/2

  14. anonymous
    • 5 years ago
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    you got it :)

  15. anonymous
    • 5 years ago
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    thanks a lot

  16. anonymous
    • 5 years ago
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    one more. I seem to have trouble converting radicals to exponentials

  17. anonymous
    • 5 years ago
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    trying to figure out the integral of dt/3 root of t

  18. anonymous
    • 5 years ago
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    I meant cube root of t

  19. anonymous
    • 5 years ago
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    let me write it out \[dt/\sqrt[3]{t}\]

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