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3/2*x^(4/3)-9/5*x^(5/3)+C using the power rule for integrals.

I need some clarification on converting radical in denominator to numerator in exponential form

Ok I think I might have got it...except the 9/5 how did you get that?

shouldn't it be 3/5 * x ^ (5/3)?

+C. I did make a mistake initially.

\[2/ \sqrt[3]{x} - \sqrt[3]{x^2}\]

this is my question

Yes. I know that. Haha.

3x^(2/3)-3/5*x^(5/3)+C. Your 3 threw me off.

sorry about that.. now it totally makes sense, thanks

Fan me then. :D

can I do one and you check and see if still understand

\[dt/\sqrt[3]{t}\]

so i get 3/2* t^2/3 +c

Yup. :)

i also get confused about ln|x| stuff

example (2x^4 - x)/ x^3 dx = I get x^2 +x^-1 +c

Ask a new question about this preferably. I don't wanna clutter one question up.

ok I just want to know why can't I write ln|x| for x^-1

You should be able to?

The integral of x^-1 is ln|x|+C

I am good on this one now
thanks again

It should be ln|x| because you can't take a log of a negative number.