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anonymous

  • 5 years ago

indefinite integral of (2/cubed root of x) - 3 cubed root of x^2

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  1. anonymous
    • 5 years ago
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    3/2*x^(4/3)-9/5*x^(5/3)+C using the power rule for integrals.

  2. anonymous
    • 5 years ago
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    I need some clarification on converting radical in denominator to numerator in exponential form

  3. anonymous
    • 5 years ago
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    I always get confused. so if you could list a few of them and show me I will be able to apply the power rule for intgrals thanks

  4. anonymous
    • 5 years ago
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    Ok I think I might have got it...except the 9/5 how did you get that?

  5. anonymous
    • 5 years ago
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    shouldn't it be 3/5 * x ^ (5/3)?

  6. anonymous
    • 5 years ago
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    Hold on. We're trying to integrate 2*x^(-1/3)-3*x^(2/3). So... using integral rule, 2*1/(1-1/3)*x^(2/3)-3*1/(1+2/3)*x^(5/3)= 3x^(2/3)-9/5*x^(5/3)

  7. anonymous
    • 5 years ago
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    +C. I did make a mistake initially.

  8. anonymous
    • 5 years ago
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    \[2/ \sqrt[3]{x} - \sqrt[3]{x^2}\]

  9. anonymous
    • 5 years ago
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    this is my question

  10. anonymous
    • 5 years ago
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    Yes. I know that. Haha.

  11. anonymous
    • 5 years ago
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    3x^(2/3)-3/5*x^(5/3)+C. Your 3 threw me off.

  12. anonymous
    • 5 years ago
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    sorry about that.. now it totally makes sense, thanks

  13. anonymous
    • 5 years ago
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    Fan me then. :D

  14. anonymous
    • 5 years ago
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    can I do one and you check and see if still understand

  15. anonymous
    • 5 years ago
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    \[dt/\sqrt[3]{t}\]

  16. anonymous
    • 5 years ago
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    so i get 3/2* t^2/3 +c

  17. anonymous
    • 5 years ago
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    Yup. :)

  18. anonymous
    • 5 years ago
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    i also get confused about ln|x| stuff

  19. anonymous
    • 5 years ago
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    example (2x^4 - x)/ x^3 dx = I get x^2 +x^-1 +c

  20. anonymous
    • 5 years ago
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    Ask a new question about this preferably. I don't wanna clutter one question up.

  21. anonymous
    • 5 years ago
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    ok I just want to know why can't I write ln|x| for x^-1

  22. anonymous
    • 5 years ago
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    You should be able to?

  23. anonymous
    • 5 years ago
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    The integral of x^-1 is ln|x|+C

  24. anonymous
    • 5 years ago
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    ok.. that's all I want to know.. it's sometimes text book shows one way and the other time it shows ln |x| without any explanation

  25. anonymous
    • 5 years ago
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    I am good on this one now thanks again

  26. anonymous
    • 5 years ago
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    It should be ln|x| because you can't take a log of a negative number.

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