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anonymous
 5 years ago
find Particular antiderivative satisfy the given condition
R'(x) = 600 0.6x; R(0) = 0
anonymous
 5 years ago
find Particular antiderivative satisfy the given condition R'(x) = 600 0.6x; R(0) = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Integrate. R(x)=600x0.3x^2+C. R(0)=C, so C=0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0got you.. that's what I thought but I was not confident enough to determine if it is right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ah, well, there you go.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are fast let me post another question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so can I show you one I did to make sure I really got it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure. can you fan me again as well? :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dR/dt = 100/t^2 R(1) = 400 so I came upt with R= 100^t +500

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did it earlier..I can do it again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it won't allow me to fan you again.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You should be able to do it once per question, I think. Anyhow, you did it correctly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok.. I will post another question then I wil fan you
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