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anonymous

  • 5 years ago

find Particular antiderivative satisfy the given condition R'(x) = 600 -0.6x; R(0) = 0

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  1. anonymous
    • 5 years ago
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    Integrate. R(x)=600x-0.3x^2+C. R(0)=C, so C=0.

  2. anonymous
    • 5 years ago
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    got you.. that's what I thought but I was not confident enough to determine if it is right

  3. anonymous
    • 5 years ago
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    Ah, well, there you go.

  4. anonymous
    • 5 years ago
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    you are fast let me post another question

  5. anonymous
    • 5 years ago
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    so can I show you one I did to make sure I really got it

  6. anonymous
    • 5 years ago
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    Sure. can you fan me again as well? :D

  7. anonymous
    • 5 years ago
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    dR/dt = 100/t^2 R(1) = 400 so I came upt with R= 100^t +500

  8. anonymous
    • 5 years ago
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    I did it earlier..I can do it again

  9. anonymous
    • 5 years ago
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    it won't allow me to fan you again.

  10. anonymous
    • 5 years ago
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    You should be able to do it once per question, I think. Anyhow, you did it correctly.

  11. anonymous
    • 5 years ago
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    Ok.. I will post another question then I wil fan you

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spraguer (Moderator)
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