## anonymous 5 years ago (4p3+28p+43p-21)/2p+7

1. bahrom7893

Did you mean: (4p3+28p+43p-21)/2p+7 or (4p3+28p+43p-21)/(2p+7)

2. anonymous

the second one

3. bahrom7893

okay so: rewrite the top as: [4p(p^2+7)+43p-21)]/(2p+7)

4. bahrom7893

[4p(p^2+7)+43p-21)]/(2p+7) = [p{4(p^2+7)+43}-21)]/(2p+7)

5. bahrom7893

this is kinda hard to simplify r u sure the problem is correct?

6. anonymous

its 4p squared +28 p squared +43p -21 divided by 2p+7 i meant 4p cubed

7. bahrom7893

okay

8. anonymous

does that seem right

9. bahrom7893

\[(4p^2 + 28p^2 + 43p -21)/(2p+7)\] Like this?

10. anonymous

does that seem right

11. anonymous

exactly but its 4p cubed

12. bahrom7893

\[(4p^3 + 28p^2 + 43p -21)/(2p+7)\]?

13. anonymous

yep

14. bahrom7893

okay so: factor out 4p^2 from the first two expressions: \[(4p^2(p + 7) + 43p -21)/(2p+7)\]?

15. anonymous

i'm confussed

16. bahrom7893

Look at this only: 4p^3 + 28p^2 = 4p^2(p + 7)

17. bahrom7893

do u get it?

18. anonymous

what does ^ mean

19. bahrom7893

to the power (four p cubed)

20. anonymous

okay so wat answer did you come up with i got 6r8p

21. bahrom7893

where the heck did r come from?

22. bahrom7893

23. anonymous

remain

24. bahrom7893

I got 16p^2 + 56p - 24?

25. bahrom7893

woops I meant (1/8)*(16p^2 + 56p - 24)