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(4p3+28p+43p-21)/2p+7

Mathematics
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Did you mean: (4p3+28p+43p-21)/2p+7 or (4p3+28p+43p-21)/(2p+7)
the second one
okay so: rewrite the top as: [4p(p^2+7)+43p-21)]/(2p+7)

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Other answers:

[4p(p^2+7)+43p-21)]/(2p+7) = [p{4(p^2+7)+43}-21)]/(2p+7)
this is kinda hard to simplify r u sure the problem is correct?
its 4p squared +28 p squared +43p -21 divided by 2p+7 i meant 4p cubed
okay
does that seem right
\[(4p^2 + 28p^2 + 43p -21)/(2p+7)\] Like this?
does that seem right
exactly but its 4p cubed
\[(4p^3 + 28p^2 + 43p -21)/(2p+7)\]?
yep
okay so: factor out 4p^2 from the first two expressions: \[(4p^2(p + 7) + 43p -21)/(2p+7)\]?
i'm confussed
Look at this only: 4p^3 + 28p^2 = 4p^2(p + 7)
do u get it?
what does ^ mean
to the power (four p cubed)
okay so wat answer did you come up with i got 6r8p
where the heck did r come from?
what is r? radical?
remain
I got 16p^2 + 56p - 24?
woops I meant (1/8)*(16p^2 + 56p - 24)

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