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## anonymous 5 years ago (z^2)/(2z+14) multiply (2z+14)/(2z^6)

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1. anonymous

$\frac{z^2}{2z + 14} \times \frac{2z + 14}{2z^6}$ note (2z + 14) cancels, and z^2 will cancel partially with 2z^6, leaving: $\frac{1}{2z^4}$

2. anonymous

thanks again I'm a bit hopeless at this, right now anyway

3. anonymous

Don't give up! Let me know what I wrote makes sense, or you need more help

4. anonymous

yes I understand it very well

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